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mia-accounting/src/accounting/unmatched_offset/queries.py

51 lines
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Python

# The Mia! Accounting Project.
# Author: imacat@mail.imacat.idv.tw (imacat), 2023/4/8
# Copyright (c) 2023 imacat.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
"""The queries for the unmatched offset management.
"""
import sqlalchemy as sa
from accounting import db
from accounting.models import Account, JournalEntryLineItem
def get_accounts_with_unmatched_offsets() -> list[Account]:
"""Returns the accounts with unmatched offsets.
:return: The accounts with unmatched offsets, with the "count" property set
to the number of unmatched offsets.
"""
count_func: sa.Label \
= sa.func.count(JournalEntryLineItem.id).label("count")
select: sa.Select = sa.select(Account.id, count_func)\
.select_from(Account).join(JournalEntryLineItem, isouter=True)\
.filter(Account.is_need_offset,
JournalEntryLineItem.original_line_item_id.is_(None),
sa.or_(sa.and_(Account.base_code.startswith("2"),
JournalEntryLineItem.is_debit),
sa.and_(Account.base_code.startswith("1"),
sa.not_(JournalEntryLineItem.is_debit))))\
.group_by(Account.id)\
.having(count_func > 0)
counts: dict[int, int] \
= {x.id: x.count for x in db.session.execute(select)}
accounts: list[Account] = Account.query.filter(Account.id.in_(counts))\
.order_by(Account.base_code, Account.no).all()
for account in accounts:
account.count = counts[account.id]
return accounts