Added the unmatched offset list and the offset matcher.

src/accounting/unmatched_offset/queries.py

@@ -0,0 +1,50 @@
+# The Mia! Accounting Project.
+# Author: imacat@mail.imacat.idv.tw (imacat), 2023/4/8
+
+#  Copyright (c) 2023 imacat.
+#
+#  Licensed under the Apache License, Version 2.0 (the "License");
+#  you may not use this file except in compliance with the License.
+#  You may obtain a copy of the License at
+#
+#      http://www.apache.org/licenses/LICENSE-2.0
+#
+#  Unless required by applicable law or agreed to in writing, software
+#  distributed under the License is distributed on an "AS IS" BASIS,
+#  WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
+#  See the License for the specific language governing permissions and
+#  limitations under the License.
+"""The queries for the unmatched offset management.
+
+"""
+import sqlalchemy as sa
+
+from accounting import db
+from accounting.models import Account, JournalEntryLineItem
+
+
+def get_accounts_with_unmatched_offsets() -> list[Account]:
+    """Returns the accounts with unmatched offsets.
+
+    :return: The accounts with unmatched offsets, with the "count" property set
+        to the number of unmatched offsets.
+    """
+    count_func: sa.Label \
+        = sa.func.count(JournalEntryLineItem.id).label("count")
+    select: sa.Select = sa.select(Account.id, count_func)\
+        .select_from(Account).join(JournalEntryLineItem, isouter=True)\
+        .filter(Account.is_need_offset,
+                JournalEntryLineItem.original_line_item_id.is_(None),
+                sa.or_(sa.and_(Account.base_code.startswith("2"),
+                               JournalEntryLineItem.is_debit),
+                       sa.and_(Account.base_code.startswith("1"),
+                               sa.not_(JournalEntryLineItem.is_debit))))\
+        .group_by(Account.id)\
+        .having(count_func > 0)
+    counts: dict[int, int] \
+        = {x.id: x.count for x in db.session.execute(select)}
+    accounts: list[Account] = Account.query.filter(Account.id.in_(counts))\
+        .order_by(Account.base_code, Account.no).all()
+    for account in accounts:
+        account.count = counts[account.id]
+    return accounts